(1/5)^x-2=125x/2

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Solution for (1/5)^x-2=125x/2 equation: 



(1/5)^x-2=125x/2

We move all terms to the left:

(1/5)^x-2-(125x/2)=0



Domain of the equation: 5)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)^x-(+125x/2)-2=0

We get rid of parentheses

(+1/5)^x-125x/2-2=0

We calculate fractions


-625x^2)/5^x*2)+()/5^x*2)+(-2=0

We can not solve this equation

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